DC Power Supply 12

Voltage multipliers

 A special rectifier circuit voltage multiplier output which is theoretically an integer times the AC peak input, for example, 2, 3, or 4 times the AC peak input. Therefore, it is possible to get 200 VDC from Vpeak AC source using duplicate 100, 400 VDC from quadrupler. Any load in a practical circuit will lower these voltages.An application of DC voltage doubler power supply capable of using either 240 VAC or 120 VAC source. Supply using a switch selected full-wave bridge to produce about 300 VDC from a 240 VAC source. Position 120 V switch rewires the bridge as a duplicate of producing about 300 VDC from 120 VAC. In both cases, 300 VDC is produced. This is the input to the switching regulator producing lower voltages for powering, say, a personal computer.Half-wave voltage in Figure below (a) consists of two circuits: a clamper at the detector (b) and peak (half-wave rectifier) ​​in Figure prior, shown in modified form in Figure below (c). C2 has been added to the peak detector (half-wave rectifier).

 the half-wave voltage doubler (a) consists of (b) clamper and (c) a half-wave rectifier.

Refer to Figure above (b), C2 charges to 5 V (4.3 V considering the diode drop) on the negative half cycle of the AC input. Is based on the right end of the run D2. The left end is charged at the negative peak AC input. This is the operation of the clamper.
During the positive half cycle, half-wave rectifier comes into play at Figure above (c). D2 diode circuit since it is reverse biased. C2 is now in series with the source voltage. Note polarity generator and C2, series help. Thus, rectifier D1 view of 10 V at the top of the sinewave, 5 V from generator and 5 V from C2. D1 run wave v (1) (Figure below), charging C1 peak sine wave riding on 5 V DC (Figure below v (2)). Wave v (2) is a duplicate output, stable at 10 V (8.6 V with diode drops) after a few cycles of sinewave input.